3x^2-6x-65=0

Solution for 3x^2-6x-65=0 equation:

3x^2-6x-65=0

a = 3; b = -6; c = -65;
Δ = b2-4ac
Δ = -62-4·3·(-65)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{51}}{2*3}=\frac{6-4\sqrt{51}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{51}}{2*3}=\frac{6+4\sqrt{51}}{6}
$